3x^(1/2)+5x^(1/4)=2

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Solution for 3x^(1/2)+5x^(1/4)=2 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

3*x^(1/2)+5*x^(1/4) = 2 // - 2

3*x^(1/2)+5*x^(1/4)-2 = 0

t_1 = x^(1/4)

3*t_1^2+5*t_1^1-2 = 0

3*t_1^2+5*t_1-2 = 0

DELTA = 5^2-(-2*3*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)-5)/(2*3) or t_1 = (-49^(1/2)-5)/(2*3)

t_1 = 1/3 or t_1 = -2

t_1 = -2

x^(1/4)+2 = 0

1*x^(1/4) = -2 // : 1

x^(1/4) = -2

( -2 < 0 i 1/4 in (0:1) ) => x naleu017Cy do O

t_1 = 1/3

x^(1/4)-1/3 = 0

1*x^(1/4) = 1/3 // : 1

x^(1/4) = 1/3

x^(1/4) = 1/3 // ^ 4

x = 1/81

x = 1/81

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